A transformer has primary turns N_p = 100 and secondary turns N_s = 50. If the primary voltage is 480 V, what is the secondary voltage V_s?

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Multiple Choice

A transformer has primary turns N_p = 100 and secondary turns N_s = 50. If the primary voltage is 480 V, what is the secondary voltage V_s?

Explanation:
In an ideal transformer, voltages scale with the turns ratio: Vs/Vp = Ns/Np. Here Ns/Np = 50/100 = 0.5, so the secondary voltage is 480 V × 0.5 = 240 V. This means the transformer steps the voltage down by a factor of two. For power balance, the current would roughly double on the secondary (Vp Ip ≈ Vs Is).

In an ideal transformer, voltages scale with the turns ratio: Vs/Vp = Ns/Np. Here Ns/Np = 50/100 = 0.5, so the secondary voltage is 480 V × 0.5 = 240 V. This means the transformer steps the voltage down by a factor of two. For power balance, the current would roughly double on the secondary (Vp Ip ≈ Vs Is).

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